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Topic: Temperature change and heat capacity.. final temp  (Read 4062 times)

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Offline FLgirl

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Temperature change and heat capacity.. final temp
« on: October 27, 2012, 06:53:15 PM »
A 55.0 g aluminum block initially at 27.5 degree C absorbs 725 J of heat. What is the final temperature of the aluminum?

ANSWER: Tf = 42.1 C

Now... how do I get to the answer?  :D

Offline Borek

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Re: Temperature change and heat capacity.. final temp
« Reply #1 on: October 27, 2012, 07:10:26 PM »
Calculate ΔT from the given data.
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Offline FLgirl

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Re: Temperature change and heat capacity.. final temp
« Reply #2 on: October 27, 2012, 07:20:22 PM »
OMG WOW thank you for being so clear! I didn't know to do that!

Offline Bublik

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Re: Temperature change and heat capacity.. final temp
« Reply #3 on: October 27, 2012, 10:05:45 PM »
there's a formula
q=mcΔT which is the same as q=mc(Tf-Ti)
you have m, you have Ti and you have q. you can find the c of aluminum on the internet.
then, calculate Tf

Offline Borek

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Re: Temperature change and heat capacity.. final temp
« Reply #4 on: October 28, 2012, 04:38:52 AM »
You know q=mcΔT as you have already listed this equation, even if not in this thread. Solve for ΔT. Once you solve for ΔT just plug and chug.

It is not clear why you can't solve the question, that's why we ask you to show some work, so that we know what is the problem. From other threads here and elsewhere I am starting to believe you should start with working on your basic algebra skills.
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