Just the other day I was looking at the s-elements and found out that Li is the strongest reducing agent (- 3.05V). This is a little strange as with other elements (Na, K, Rb, Cs) the standard electrode potential decreases from - 2,71V to - 2,92V as you go down in the group.
Add to this the ionization energy of -5,39eV for Li and a steady decrease as you go down in the group and it's a bit of a mystery.
Now, there is an explanation in my textbook, and it goes like this: If we look at redox-potential as
M(s)
M
+(aq) + e
- by using Hess's law we can divide this process into three separate subprocesses:
(1) M(s)
M(g)
(2) M(g)
M
+(g) + e
-(3) M
+(g) + aq
M
+(aq)
(1) is just separation of atoms. Sublimation energy is about the same for all s-elements
(2) is ionization energy. You need to spend about 5,39 eV for Li to make it an ion.
(3) The Li
+ is put in water and hydrated. Energy is released Δ
hydHThis Δ
hydH is more than enough to compensate for the (relatively) high 5,39 eV ionization energy, because, if I remember correctly from general chemistry, the smaller the ion the larger the Δ
hydH.
My question is this: Why? What happens on the molecular scale? I "get" all of thermodynamics here, but when I tried to find where does this energy come from, I can't find anything. I looked in Atkins' Physical Chemistry and inorganic and general chemistry textbooks. Nothing.
Any useful response will be rewarded by a mole snack. (or even two
)