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Topic: Calculating "Position of Equilibrium"  (Read 2317 times)

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Offline Big-Daddy

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Calculating "Position of Equilibrium"
« on: January 09, 2013, 10:27:26 AM »
What is meant by "position of equilibrium" and what are the steps taken to calculate it (for a given set of initial concentrations at a set temperature and pressure)?

Offline Hunter2

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Re: Calculating "Position of Equilibrium"
« Reply #1 on: January 10, 2013, 03:35:58 AM »
This means is the equilibrium on the side of the educt or products and how far it is. It will be expressed by the K.

A+B => C+D   K = c(C)*c(D)/(c(A)*c(B))

Offline Big-Daddy

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Re: Calculating "Position of Equilibrium"
« Reply #2 on: January 10, 2013, 12:35:50 PM »
This means is the equilibrium on the side of the educt or products and how far it is. It will be expressed by the K.

A+B => C+D   K = c(C)*c(D)/(c(A)*c(B))

You speak of the equilibrium constant, not the position of the equilibrium. Let me point out the difference. Keq stays constant if I change the concentration of the reactants or products by adding or taking some. But if I add A, then the position shifts, in the sense that the "equilibrium moves to the right" (more of C and D are being produced). But how does one calculate something like this?

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