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Topic: Malonate cyclic compound synthesis  (Read 2590 times)

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Offline Rutherford

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Malonate cyclic compound synthesis
« on: January 21, 2013, 10:46:22 AM »
Could someone rationalize the first step in this synthesis? What is happening there?

Offline discodermolide

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Re: Malonate cyclic compound synthesis
« Reply #1 on: January 21, 2013, 10:47:55 AM »
The first step is a simple dialkylation of the malonate ester with methyl iodide.
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Offline Rutherford

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Re: Malonate cyclic compound synthesis
« Reply #2 on: January 21, 2013, 10:49:53 AM »
How does it work?

Offline discodermolide

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Re: Malonate cyclic compound synthesis
« Reply #3 on: January 21, 2013, 10:57:57 AM »
The base, NaOEt removes one of the acidic protons of the CH2 group. They are very acidic due to the electron withdrawing esters. The resulting anion is stabilised by resonance through the ester carbonyls.
Methyl iodide is the electrophile and is attacked by the carbanion to give the methylated compound.
Rinse and repeat for the remaining CH to give the dialkylated compound.

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Offline Rutherford

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Re: Malonate cyclic compound synthesis
« Reply #4 on: January 21, 2013, 11:04:34 AM »
And the last step is the same process then. Thanks.

Offline discodermolide

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Re: Malonate cyclic compound synthesis
« Reply #5 on: January 21, 2013, 11:07:24 AM »
No problem.
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