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Pressures in Kc
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Topic: Pressures in Kc (Read 2105 times)
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Ben Cohen
Regular Member
Posts: 35
Mole Snacks: +2/-2
Pressures in Kc
«
on:
January 22, 2013, 12:43:09 AM »
Hi guys,
Let's say you have 2H
+
+ 2e
-
H
2
Am I right with: Kc = [H
2
] / [H
+
]
2
And then what is Kp? Is Kp = P
H
2
/ [H
+
]
2
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Hunter2
Sr. Member
Posts: 2369
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Gender:
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Re: Pressures in Kc
«
Reply #1 on:
January 22, 2013, 01:06:11 AM »
Read here:
http://chemwiki.ucdavis.edu/Physical_Chemistry/Chemical_Equilibrium/The_Equilibrium_Constant/Calculating_An_Equilibrium_Concentration_From_An_Equilibrium_Constant/Writing_Equilibrium_Constant_Expressions_Involving_Gases/Gas_Equilibrium_Constants,_Kc_And_Kp
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Ben Cohen
Regular Member
Posts: 35
Mole Snacks: +2/-2
Re: Pressures in Kc
«
Reply #2 on:
January 22, 2013, 08:06:16 PM »
So to make sure I understand....
For the reaction HCN (aq)
HCN (g)
Kc = [HCN (g) ] / [HCN (aq)] where both are expressed in mol / L
Kp = P
HCN(g)
/ [HCN (aq) ] with HCN (g) in atmospheres and HCN (aq) is in mol/L
Is this correct?
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