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Topic: Pressures in Kc  (Read 2105 times)

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Offline Ben Cohen

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Pressures in Kc
« on: January 22, 2013, 12:43:09 AM »
Hi guys,

Let's say you have 2H+ + 2e-  ::equil::  H2

Am I right with: Kc = [H2] / [H+]2
And then what is Kp? Is Kp = PH2 / [H+]2


Offline Ben Cohen

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Re: Pressures in Kc
« Reply #2 on: January 22, 2013, 08:06:16 PM »
So to make sure I understand....

For the reaction HCN (aq)  ::equil:: HCN (g)

Kc = [HCN (g) ] / [HCN (aq)]  where both are expressed in mol / L
Kp = PHCN(g) / [HCN (aq) ]  with HCN (g) in atmospheres and HCN (aq) is in mol/L

Is this correct?

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