January 12, 2025, 09:01:22 PM
Forum Rules: Read This Before Posting


Topic: Chemical equilibrium question  (Read 2350 times)

0 Members and 1 Guest are viewing this topic.

Offline Anthasci

  • Regular Member
  • ***
  • Posts: 37
  • Mole Snacks: +1/-0
Chemical equilibrium question
« on: January 26, 2013, 07:02:06 PM »
I've frantically tried to solve this problem, but I just feel like there's something missing ... Here it is:

Quote
A reaction container with V=100dm3 is filled with H2(g) and P2(g) at T=800K. The starting partial pressures of both components are equal to 1 bar. Once the reaction:

3H2(g) + P2(g)  ::equil:: 2PH3(g)

reaches equilibrium, the total pressure inside the container is 1,9 bar. Calculate the equilibrium constant K for the reaction at 800K.

[K=0.012]

I started by calculating the total amount of moles of reactants (I assumed the container is fully filled) and given that pressure is 2 bar, I came with the result ntot = 0,33256 mol
But when I wanted to calculate the molar fractions, I found out I'm missing information about pressure of a pure component
pi = xi · p*i would then ideally give me the molar fractions and I'd be left with only one variable, β for example (where 2β is the amount of generated phosphane and 3β and β are the amounts of hydrogen and phosphorous, respectively, that reacted. I'm pretty sure I'm on the right way here, but overlooking some detail. Anyone care to point me in the right direction?

Thanks

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27897
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Chemical equilibrium question
« Reply #1 on: January 27, 2013, 04:00:25 AM »
Why do you start with sum of initial amounts instead of calculating individual initial amounts?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline curiouscat

  • Chemist
  • Sr. Member
  • *
  • Posts: 3006
  • Mole Snacks: +121/-35
Re: Chemical equilibrium question
« Reply #2 on: January 27, 2013, 04:08:22 AM »
By PV=nRT how many total moles left at end?

Also how many mols of each component at start?

Offline Anthasci

  • Regular Member
  • ***
  • Posts: 37
  • Mole Snacks: +1/-0
Re: Chemical equilibrium question
« Reply #3 on: January 27, 2013, 11:13:30 AM »
Oh, I get it now ... the moles of both starting components are the same and the mixture at the end contains 0,35 moles of gas. This should give me the required information to calculate the K.

I also provided the wrong equation, it should be pi = xi · p because I was calculating (or trying to) the fractions in a liquid and forgetting that I already have two gaseous phases. Thanks to both :) It's amazing how late hours can distort your thinking process :D

Sponsored Links