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Topic: Aldol Condensation  (Read 9136 times)

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Offline orgopete

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Re: Aldol Condensation
« Reply #15 on: January 19, 2013, 11:25:35 PM »
CCCC(C)C=O>>CCCC(C)C(O)C(C)(C=O)CCC

CCCC(C)C(O)C(C)(C=O)CCC>>CCCC(C)=CC(C)(C=O)CCC

I'd like to see a reference for tis reaction. I don't think you can form his wih NaOH.
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Offline curiouscat

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Re: Aldol Condensation
« Reply #16 on: January 20, 2013, 12:13:26 AM »

I'd like to see a reference for tis reaction. I don't think you can form his wih NaOH.

No clue at all. You might be right.

I was only typesetting his hard-to-read handwritten equations.

Offline souro10

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Re: Aldol Condensation
« Reply #17 on: January 20, 2013, 01:49:39 AM »

I'd like to see a reference for tis reaction. I don't think you can form his wih NaOH.

Why not? Which step? The aldol step or the condensation step?

I can't think of any objection one could have with the aldol step.
The condensation product is wrong though. The base will pull a proton from the most acidic (next to the carbonyl group, in this case there's only one such carbon ) source, leading to enolization, double bond migration, and loss of hydroxyl group to produce an alpha-beta unsaturated aldehyde.

Offline curiouscat

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Re: Aldol Condensation
« Reply #18 on: January 20, 2013, 02:16:52 AM »

I'd like to see a reference for tis reaction. I don't think you can form his wih NaOH.

The base will pull a proton from the most acidic (next to the carbonyl group, in this case there's only one such carbon ) source, leading to enolization, double bond migration, and loss of hydroxyl group to produce an alpha-beta unsaturated aldehyde.

This?

CCCC(C)C(O)C(C)(C=O)CCC>>CCCC(C)C=C(C)(C=O)CCC

Offline souro10

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Re: Aldol Condensation
« Reply #19 on: January 20, 2013, 02:11:50 PM »

I'd like to see a reference for tis reaction. I don't think you can form his wih NaOH.

The base will pull a proton from the most acidic (next to the carbonyl group, in this case there's only one such carbon ) source, leading to enolization, double bond migration, and loss of hydroxyl group to produce an alpha-beta unsaturated aldehyde.

This?

CCCC(C)C(O)C(C)(C=O)CCC>>CCCC(C)C=C(C)(C=O)CCC

Precisely!  :)

Offline sjb

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Re: Aldol Condensation
« Reply #20 on: January 20, 2013, 04:25:01 PM »
Texas carbon ahoy?

Offline souro10

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Re: Aldol Condensation
« Reply #21 on: January 21, 2013, 02:16:00 AM »
Sorry, I hadn't noticed the substituent!  :( Too much ignorance.

Offline neobenzene

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Re: Aldol Condensation
« Reply #22 on: January 26, 2013, 01:51:07 AM »
So, what is the final, correct answer??

Offline souro10

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Re: Aldol Condensation
« Reply #23 on: January 27, 2013, 07:30:27 AM »
The aldol product is the correct answer. It will not dehydrate in this case I think.

Offline neobenzene

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Re: Aldol Condensation
« Reply #24 on: February 02, 2013, 10:23:25 AM »
Why won't it dehydrate?

Offline orgopete

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Re: Aldol Condensation
« Reply #25 on: February 02, 2013, 09:45:48 PM »
Why won't it dehydrate?

The aldol addition product lacks an acidic proton, so elimination is similar to a dehydration of 2-butanol with base. the most acidic hydrogen would be the OH, further hampering elimination.

It would be difficult to predict exactly what will be the result. The aldol addition product could be the result, but other reactions might also occur with the aldehyde. 
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Offline neobenzene

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Re: Aldol Condensation
« Reply #26 on: February 03, 2013, 04:44:01 AM »
Quote
The aldol addition product lacks an acidic proton, so elimination is similar to a dehydration of 2-butanol with base. the most acidic hydrogen would be the OH, further hampering elimination.

It would be difficult to predict exactly what will be the result. The aldol addition product could be the result, but other reactions might also occur with the aldehyde.

Thanks, orgopete!

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