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Topic: Help balancing redox reaction  (Read 10410 times)

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Offline chanelo

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Help balancing redox reaction
« on: February 18, 2013, 02:05:18 PM »
"The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form of Sb3+(aq). The Sb3+(aq) is completely oxidized by an aqueous solution of BrO3-(aq). Complete and balance the equation for this reaction in acidic solution."

My answer was
 BrO3-(aq) + 3Sb3+(aq) + 6H+(aq)  :rarrow: Br-(aq) + 3Sb5+(aq) + 3H2O(l)

I've tried going through it over and over and keep getting this same answer, which is wrong. Can someone please tell me what's wrong with this equation?

Offline Borek

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Re: Help balancing redox reaction
« Reply #1 on: February 18, 2013, 03:28:42 PM »
Show how you are balancing.
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Offline AWK

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Re: Help balancing redox reaction
« Reply #2 on: February 18, 2013, 06:44:26 PM »
AWK

Offline chanelo

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Re: Help balancing redox reaction
« Reply #3 on: February 19, 2013, 10:59:29 PM »
Sure, this is my work:

BrO3-  :rarrow: Br-
BrO3-  + 6H+ + 6e- :rarrow: Br- + 3H2O

Sb3+  :rarrow: Sb5+ + 2e-
3Sb3+  :rarrow: 3Sb5+ + 6e-

Combined, e- cancel out:
3Sb3+ + BrO3-  + 6H+ :rarrow: 3Sb5+ + Br- + 3H2O

Offline Borek

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Re: Help balancing redox reaction
« Reply #4 on: February 20, 2013, 04:02:27 AM »
Very good. And why do you think it is wrong?

Are atoms balanced?

Are charges balanced?

If they are, the equation is balanced, period.
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Offline chanelo

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Re: Help balancing redox reaction
« Reply #5 on: February 20, 2013, 07:45:01 PM »
Everything looks balanced to me but Sapling keeps saying it's wrong.

Offline Borek

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Re: Help balancing redox reaction
« Reply #6 on: February 21, 2013, 04:15:53 AM »
Hard to say. Can be some bug. People often complain about the way answers have to be entered into these automatic systems.

What I don't like about the equation is that there is no such thing as Sb5+. Sb is oxidized to Sb(V), but it is not present as the naked +5 cation.
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Offline chanelo

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Re: Help balancing redox reaction
« Reply #7 on: February 21, 2013, 12:27:11 PM »
Yup, you're right, it was just a bug. The answer was right, not sure why it wasn't accepting it. Thanks!

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