What is the pH of a 0.25 M methylamine solution?
The formula is ch3nh2
so what I did was .25*2=.5
-log(.5)=.30
Calculate the pH of a 0.50 M solution of potassium cyanide
the formula is kcn
I did -log(.5)=.30
Am I doing this right? I feel that since these aren't strong acids/bases there should be more work involved