[Stovn0611]

I would use the Ideal Gas Law to solve for moles of N2 then convert to grams of N2

[Vileblood]

Hm so i tried what i suggested n= PV/RT
n = 0.9525 atm N2(0.0189 L N2)   = .0007388 moles N2
      0.08206 L atm/mol K (296.95 K)

0.0007388 moles N2 x 28.014 g/mol  =  0.02070 g N2
                              1 mole N2

0.02070 g N2  x 100 = 8.647% N2
0.2394 g sample

the question is asking for percent nitrogen though..damn just realized