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Topic: Solution Stoichiometry  (Read 1616 times)

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Offline DSG124

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Solution Stoichiometry
« on: March 05, 2013, 03:42:25 PM »
Hey all,

So in an example in my text on stoichiometry, the first step is to find the limiting reagent of:

2NaOH+ZnCl2=2NaCl + Zn(OH)2
.200mol/L, 50mL for each.
To find the moles however, they do:
NaOH=.100mol/Lx.0500L and ZnCl2=.100mol/Lx.0500L.

I don't understand why both are given .100mol/L. It would make sense for NaOH since it can be divided by 2 for the balanced equation, but ZnCl2 only has one, so there must be another reason why .100mol/L is given.

Any help would be appreciated!

Offline Borek

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Re: Solution Stoichiometry
« Reply #1 on: March 05, 2013, 04:40:01 PM »
Must be an error in the text, number of moles is n=CV. 0.200M*0.050L for both substances.
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