Topic: How can I balance this equation to find theoretical yield? (Read 2696 times)

theanonymous · « **on:** March 14, 2013, 10:05:09 AM »

C₉H₈O + C₂₅H₂₂ClP :rarrow:NaOH:rarrow: C₁₆H₁₄ + C₁₈H₁₅OP

sjb · « **Reply #1 on:** March 14, 2013, 10:41:27 AM »

Quote from: theanonymous on March 14, 2013, 10:05:09 AM

C₉H₈O + C₂₅H₂₂ClP :rarrow:NaOH:rarrow: C₁₆H₁₄ + C₁₈H₁₅OP

It might be a bit easier if you show your structures, or at least some semblance of the reaction you are carrying out (a Wittig? looking at ChemSpider hits for C₂₅H₂₂ClP).

theanonymous · « **Reply #2 on:** March 14, 2013, 11:39:19 AM »

Quote from: sjb on March 14, 2013, 10:41:27 AM

Quote from: theanonymous on March 14, 2013, 10:05:09 AM
C₉H₈O + C₂₅H₂₂ClP :rarrow:NaOH:rarrow: C₁₆H₁₄ + C₁₈H₁₅OP

It might be a bit easier if you show your structures, or at least some semblance of the reaction you are carrying out (a Wittig? looking at ChemSpider hits for C₂₅H₂₂ClP).

Yes! Sorry I was away - I keep changing classes!.

Ok so the reaction is.

Cinnamaldehyde + benzyltriphenyl phosphonium chloride ---NaOH--> 1,3 diphenyl-1-,3 butadiene + triphenylphosphine oxide

theanonymous · « **Reply #3 on:** March 14, 2013, 11:44:48 AM »

sjb · « **Reply #4 on:** March 14, 2013, 01:04:21 PM »

OK, so can you draw the mechanism of this out? How many equivalents of aldehyde do you need per bromide (or vice versa)?

Topic: How can I balance this equation to find theoretical yield? (Read 2696 times)

theanonymous

How can I balance this equation to find theoretical yield?

sjb

Re: How can I balance this equation to find theoretical yield?

theanonymous

Re: How can I balance this equation to find theoretical yield?

theanonymous

Re: How can I balance this equation to find theoretical yield?

sjb

Re: How can I balance this equation to find theoretical yield?

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