[wow]

Suppose an enzyme alters the ΔG‡ of a reaction from 52 kJ mol-1 to 27 kJ mol-1.
How much faster will the catalyzed reaction proceed at 300.6K as compared to the
uncatalyzed reaction? Show your work. Remember: at 300.6K, RT = 2.5 kJ mol-1.


a.
If the enzyme in (a) is exposed to a mixed inhibitor, would you expect the
rate-enhancement to change? Why or why not?

[Babcock_Hall]

It is a forum rule that you must show your work.  Do you know what a mixed inhibitor is?  Do you have a conceptual idea of what ΔG‡ is?

[wow]

yes

[Babcock_Hall]

OK, good, but you still need to show your attempt at these two problems.  Forum rule.  Do you know any equations involving ΔG‡?  When you add a mixed inhibitor to an enzyme-catalyzed reaction, what do you observe?

[wow]

no i dont im sorry i forgot them

[Borek]

Then open your book or notes and check them.

[wow]

delta g =-RTlnkeq

also ln k= lnQ- delta G double dagger/ RT.  I just cant figure out how to setup up the formula correctly for the first part in order to plug in the numbers.    i know its the arrhenius forumula but cant seem to figure out how to use the info given.  can you help by suggesting a formula which i can plug in the number s ( i learn backwards usually..)