September 28, 2024, 07:21:03 PM
Forum Rules: Read This Before Posting


Topic: Optical Rotation R S  (Read 1379 times)

0 Members and 1 Guest are viewing this topic.

Offline kamikaze

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Optical Rotation R S
« on: March 17, 2013, 11:24:41 PM »
Hello, I'd like to know the optical relationship between R and S enantiomer (assuming that the compound has one stereocenter). That is, for example, if an optical rotation of R enantiomer is -28, then what would be the optical rotation of S enantiomer? Any suggestions or hints would be greatly appreciated, thanks

Offline discodermolide

  • Chemist
  • Sr. Member
  • *
  • Posts: 5038
  • Mole Snacks: +405/-70
  • Gender: Male
    • My research history
Re: Optical Rotation R S
« Reply #1 on: March 17, 2013, 11:37:29 PM »
If you know that the (R) enantiomer has a rotation of -28° then the (S) enantiomer should be +28°.

But note, unless you measure the rotation there is no relationship between the (R) and (S) configuration and optical rotation.
Development Chemists do it on Scale, Research Chemists just do it!
My Research History

Sponsored Links