Thanks a lot! I think I figured them out.
For 1, I converted them to ΔG, added them, then converted back to standard reduction potentials so (1)(96500)(1.82)+(2)(96500)(-0.28)=121590 then 121590/(3*96500)=0.42
For 2, I just set up the equation for Kb:
[OH-][HZ]/[Z-] Solved for Kb then put that under 10-14 to get Ka