OK, so here is my problem:
lithium carbonat reacts with hydrochloric acid
1) Write the balanced equation.
Here is what I get:
Li2CO3 + 2HCl ---> 2LiCl + CO2 + H2O
2) What is the excess reagent?
I think this is a 1:2 ratio;
The reaction requires 1 M (one mole) lithium chloride with 2 M (two moles)hydrochloric acid
So, does it follow then that HCl is the excess reagent because more moles of HCl (2 versus 1) are required in the reaction?
3) What happens to the excess reagent at end of experiment?
I guess since it is in ecess, it is NOT used up and remains in some form, right?
I am NOT provided any value concerning the amount of lithium carbonate and hydrochloric acid.
Is this a trick question or I am I just blind here
Any help that anyone can give on this probelm is greatly appreciated!! This one has been stumping me all day!