January 10, 2025, 12:54:11 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Heart of Fusion  (Read 5236 times)

0 Members and 1 Guest are viewing this topic.

Tom

  • Guest
Heart of Fusion
« on: June 29, 2004, 12:38:46 PM »
My calculation for the heart of fusion in a kJ/mol if 10.0 g of solid chromium which absorbs 2.82 x 103 J of heat in melting came out at 34.3 kJ/mol. Can anyone double check this for me?
      
Logged

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7976
  • Mole Snacks: +555/-93
  • Gender: Male
Re:Heart of Fusion
« Reply #1 on: June 30, 2004, 02:22:33 AM »
1 Mole of chromium weights 51.996 g.
Hence heat of fusion is (51.996/10.0)x2.82 kJ=14.7 kJ/mol (real value is 16.9)
Logged
AWK

Tom

  • Guest
Re:Heart of Fusion
« Reply #2 on: June 30, 2004, 08:32:16 AM »
Thanks, I caught what I did, I had an incorrect number for the mole.
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links