This question is irritating the hell out of me and my tutor had no idea how to solve it.
One liter of a buffer solution is prepared by dissolving 0.115 mol of NaNO2 and 0.070 mol of HCl in water. What is the pH of this solution? If the solution is diluted twofold with water, what is the pH?
The thought just occurred to me that this may be a trick question in some regard since HCl is a strong acid and NaNO2 is a salt of a weak acid, but I haven't came across a trick question in the previous 19 chapters so I'm banking on a typo?
The only other way I could possibly think to solve this is:
NaNO2 + H2O ----> NaOH + HNO2 then
HNO2 + H2O ----> H3O+ + NO2- and then
HCl + H2O -----> H3O+ + Cl-
add the [] of H3O+ and use the pH = pKa+log[CB/A] formula, but then my problem is what pKa value do I use?
I keep going back to the answer being whatever the pH of HCl calculates out to be and then for the second part dividing the [HCl] by half and using that pH value.
I know I'm over thinking this, I just don't understand why the text book would give a question like this when it doesn't fall into the normal way the book gives chapter questions.