[danshodan]

I have a wrapped box that weight 130.41 grams and i need to find the following:
Assuming your box and its wrapping are made only from cellulose C6H105, calculate the
number of molecules of cellulose contained in the box and wrapping material.
So i did the following:

130.41g C6H10O5 X 1 mol C6H10O5        6.02X10^23 mcs C6H10O5
                             ________________  X  __________________________ = 4.84 mcsC6H10O5
                            162.14g C6H10O5        1 mol C6H10O5
Am I correct?

[Borek]

4.84 mcsC6H10O5

Am I correct?

Looks like you have lost 10²³

But something is wrong with the question - cellulose is an organic polymer, not a single 6-carbon particle.

[danshodan]

Looks like you have lost 10²³

What do you mean by that?

But something is wrong with the question - cellulose is an organic polymer, not a single 6-carbon particle.

Also, im not sure what u mean, are u refering to the given formula of cellulose?

Thanks for your help

[Mitch]

He meant, you failed to multiply by 10^23 if you do the Math again you will see it does not match the answer you posted.

[danshodan]

He meant, you failed to multiply by 10^23 if you do the Math again you will see it does not match the answer you posted.

You are correct i forgot the 10²³.
The answer should be 4.84X10²³ mcsC6H10O5.
However I still am unsure about the other problem

But something is wrong with the question - cellulose is an organic polymer, not a single 6-carbon particle.

[Mitch]

It means the problem is silly, because the chemical formula for cellulose isn't C6H105.

[danshodan]

It means the problem is silly, because the chemical formula for cellulose isn't C6H105.

Im not sure, since i didnt write the question, however I looked on wikipedia.com just now and it says

Cellulose (C6H10O5)n is a long-chain polymer polysaccharide carbohydrate, of beta-glucose. It forms the primary structural component of plants and is not digestible by humans.

But that doesn't really make a difference for me, because I can't change the question; I have to go by what I am told.
So.... assuming that the formula for cellulose is what is stated in the question, have i done things right and got the correct answer

[kkrizka]

Im not sure, since i didnt write the question, however I looked on wikipedia.com just now and it says But that doesn't really make a difference for me, because I can't change the question; I have to go by what I am told.
So.... assuming that the formula for cellulose is what is stated in the question, have i done things right and got the correct answer

I think what that means is that cellulose if a long chain of n number of parts. Each part is C6H10O5. What I suppose the question is asking is how many of those parts the box has. If this is just an exercise question in your book, you shouldn't pay much attension to such details. And yes, you are correct.