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Topic: E2 mechanism help  (Read 2204 times)

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Offline craigms

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E2 mechanism help
« on: May 11, 2013, 01:27:56 AM »
Is anyone able to show me how this reaction would occur via E2?


KOBu(tertiary) in HOBu(tertiary)

I'm a bit confused doesn't the H need to be trans to the Br? In this case isn't the cyclic ring trans to the leaving group? or am I not getting it..
« Last Edit: May 11, 2013, 01:39:28 AM by craigms »
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Offline discodermolide

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Re: E2 mechanism help
« Reply #1 on: May 11, 2013, 01:40:37 AM »
You have a trans H to the Br,
it's on the ring-CH2-CH2Br One of these is trans.
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Offline craigms

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Re: E2 mechanism help
« Reply #2 on: May 11, 2013, 02:01:40 AM »
Quote from: discodermolide on May 11, 2013, 01:40:37 AM
You have a trans H to the Br,
it's on the ring-CH2-CH2Br One of these is trans.

How so? Wouldn't it look like this, the R group being trans to the Br? Please explain I'm still confused.



R = cyclohexane
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Offline hairygorillaz

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Re: E2 mechanism help
« Reply #3 on: May 11, 2013, 02:19:13 AM »
There is rotation around the Cy-CH2-CH2Br bond.
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