[Immortal]

Ok i was wondering if u go from N=1 to N=2 or N=2 to N=1 which is higher in Energy. The thing im trying to learn is when u go up the orbitals it requires  a release in energy? or absorbs energy? Or should i just use Rhyberg's Equation. cause i don't calculations are needed in certain types of quesitons related to this. unless they ask for the actual Energy.

Sample problem: Which of the following transitions in the Bohr hydrogen atom will emit the highest-energy photon?

A.   n = 1 to n = 6
B.   n = 6 to n = 1
C.   n = 7 to n = 2
D.   n = 3 to n = 8
E.   n = 1 to n = 7

Q. Would they also ask for atoms not related to hydrogen?, as this law only applies to hyrdrogen? or for all elements, and as u go up N the Energy Required to go up is smaller and smaller, therefore N=6 to N=1 is larger than N=7 to N=2?

[Mitch]

Its the difference in n that matters not the direction. For your own knowledge when you go from low n to high n you are absorbing energy, high-to-low you are releasing energy.

[Immortal]

N= 4 to N=3 is lower energy than N=3 To N=2 correct?

[Mitch]

yes

[Immortal]

So its a state function, when i calculated it whether its negative or not does not matter?, the question :
Sample problem: Which of the following transitions in the Bohr hydrogen atom will emit the highest-energy photon?

A.  n = 1 to n = 6
B.  n = 6 to n = 1
C.  n = 7 to n = 2
D.  n = 3 to n = 8
E.  n = 1 to n = 7

according to u the answer will be E.?

or since they want the E emitted it would the greatest difference from high E to Low E?

[Mitch]

or since they want the E emitted it would the greatest difference from high E to Low E?

Yeah, you should worry about that.