December 21, 2024, 12:12:35 PM
Forum Rules: Read This Before Posting


Topic: Free energy of Mixture  (Read 2372 times)

0 Members and 1 Guest are viewing this topic.

Offline Hendarte

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-1
Free energy of Mixture
« on: May 31, 2013, 03:37:19 PM »
Good, I am new for the forum and it wanted to know if someone can help me with the following problem

For a regular solution in which the components have molecules of the same size, the free energy of mixture is:
ΔGM=RT (n1LnX1+n2lnX2)+(n1+n2) X1X2w

Where n denotes the quantity of components, X is the fraction to like and w is a parameter that measures the diversion of the law of raoult. Show that for such solutions, the chemical potentials are given for:

μ11°+RT lnX1+wX22

μ22°+RT lnX2+wX21

Since I can deduce an equation to estimate the coefficients of activity of the components in the dissolution

Sponsored Links