To maintain the pH of blood at its normal value (7.4), the amount of H2CO3 in the buffer is closest to:
A) 10 x amount of NaHCO3
B) 5 x amount of NaHCO3
C) 2 x amount of NaHCO3
D Half amount of NaHCO3
I plugged in the values into Henderson-Hasselbach equation:
7.4 = 6.37 + log(HCO3 / H2CO3 )
1.03 = log(HCO3 / H2CO3 )
101.03 = HCO3 / H2CO3
If the ratio is HCO3 : H2CO3
Then wouldn't it be 10 : 1
...10 parts HCO3 to 1 part H2CO3
I'm getting confused with this final part.