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Topic: Choice of redox reaction  (Read 1827 times)

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Offline Big-Daddy

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Choice of redox reaction
« on: August 29, 2013, 07:37:10 AM »
Problem:
An acidified sample is passed through the reductor, collected, and titrated with a strong oxidizing titrant of known concentration (for example KMnO4). The most common version is the so-called Jones-reductor that contains amalgamated zinc granules.

Give the reactions that take place, and the corresponding equilibrium constants, when the following solutions are passed through a Jones-reductor:
0.01 mol/dm3 CuCl2
0.01 mol/dm3 CrCl3
0.01 mol/dm3 NH4VO3 (pH =1)

Data provided:
E°(Zn2+/Zn) = –0.76
E°(Cu2+/Cu) = 0.34
E°(Cu2+/Cu+) = 0.16
E°(Cr3+/Cr) = –0.74
E°(Cu2+/Cu+) = 0.16
E°(Cr2+/Cr) = –0.90
E°(VO2+/VO2+) = 1.00
E°(V3+/V2+) = –0.255
E°(V2+/V) = –1.13

Comment:
If I could work out what reaction takes place, there is sufficient data for me to easily work out the equilibrium constants for those reactions. So how do I work out which reactions take place?

Offline sjb

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Re: Choice of redox reaction
« Reply #1 on: August 29, 2013, 10:58:33 AM »
What determines if a reaction takes place?

Offline Big-Daddy

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Re: Choice of redox reaction
« Reply #2 on: August 29, 2013, 04:01:40 PM »
The Gibbs' free energies, so in this case the E° values would be used to give an indication. So is the process to go through the stages of reduction one by one, and whenever a certain reduction has negative E°, it won't occur (assume E° and E take the same sign), but all previous reductions will occur?

In other words, which reaction occurs has no dependence on E° of Zn2+ couple?

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