The question says to balance this reaction:
MnO4 (1-) + I2 + H(1+) --> MnO2 + I03 (1-)
I this is in a base but I have never seen an H+ on the left side before...
I balanced it without using that H and it seems to have balanced:
2H20 + 10 Mn04 (1-) + 3I2 --> 6IO3 (1-) + 10 MnO2 + 4OH(1-)
That is balanced correctly right? What is the a on the reactant side for?
Thank you