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Topic: Oxidation of Zn(s) in excess 1M NaHSO4 produces SO2 gas?  (Read 1867 times)

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Offline lpf1991

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Oxidation of Zn(s) in excess 1M NaHSO4 produces SO2 gas?
« on: November 24, 2013, 11:19:17 PM »
Zn(s) is oxidized in excess 1M NaHSO4, gives SO2 as reducer.  For this reaction, the ration of mols of oxidizer to reducer is:

Answer is 1:1

Could someone just help me understand what occurs here.  I'm guessing the NaHSO4 will dissociate, but not really sure how to proceed.

Thanks for any help.
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Offline Hunter2

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Re: Oxidation of Zn(s) in excess 1M NaHSO4 produces SO2 gas?
« Reply #1 on: November 25, 2013, 02:46:55 AM »
You have two pairs Zn/Zn2+ and SO42-/So2

develop for each the reaction equation. If Oxygen is present use H+ and H2O to balnce it.
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