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Topic: How to substitute this bromine group with alkyl chain?  (Read 4558 times)

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Offline darkdevil

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How to substitute this bromine group with alkyl chain?
« on: November 08, 2013, 11:10:18 AM »
Hi there,
Suppose I have this compound, 3-bromobenzaldehyde

And I want to substitute the bromo group with an alkyl group. I am not sure which method I shall use??
1) Suzuki coupling with alkyl broronic acid
2) Protect the aldehyde and then do grignard and then treat with alkyl halide
3) Organoaluminum method
4) others??

Offline Archer

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Re: How to substitute this bromine group with alkyl chain?
« Reply #1 on: November 08, 2013, 01:07:32 PM »
No.2 won't work, Grignard reagents don't undergo SN2 reactions.

I would try Suzuki coupling if I were attempting this.
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Offline AlphaScent

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Re: How to substitute this bromine group with alkyl chain?
« Reply #2 on: November 08, 2013, 01:14:16 PM »
I have done 10-undecyn-1-OTHP grignard addition to 1-bromo-3-pentyne at low temperatures with success. Albeit higher temps resulted in elminination. 

If you're not part of the solution, then you're part of the precipitate

Offline AlphaScent

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Re: How to substitute this bromine group with alkyl chain?
« Reply #3 on: November 08, 2013, 01:16:37 PM »
You now what.  I believe I misspoke.  Grignards do not go through Sn2.  I forgot about our good friend Copper's involvement in my reaction.  That is sure not Sn2.  I was wrong.
If you're not part of the solution, then you're part of the precipitate

Offline Archer

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Re: How to substitute this bromine group with alkyl chain?
« Reply #4 on: November 08, 2013, 01:25:07 PM »
I have done 10-undecyn-1-OTHP grignard addition to 1-bromo-3-pentyne at low temperatures with success. Albeit higher temps resulted in elminination.

Ah, ok, I have never tried this for simple C-C bond formation.
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Offline zsinger

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Re: How to substitute this bromine group with alkyl chain?
« Reply #5 on: November 08, 2013, 02:27:07 PM »
NO DOUBT SUZUKI COUPLING!  I will caution you though if you have never done it……read about it like you were a novice before you try it again, as I screwed it up about 4 times before success (and I had done it in undergrad)! 
"The answer is of zero significance if one cannot distinctly arrive at said place with an explanation"

Offline Archer

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Re: How to substitute this bromine group with alkyl chain?
« Reply #6 on: November 08, 2013, 03:27:58 PM »
You now what.  I believe I misspoke.  Grignards do not go through Sn2.  I forgot about our good friend Copper's involvement in my reaction.  That is sure not Sn2.  I was wrong.

I did wonder why this worked :) if a Grignard underwent SN2 readily then they would form only in very low yields because as they formed they would react with the starting material present.
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Offline darkdevil

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Re: How to substitute this bromine group with alkyl chain?
« Reply #7 on: November 09, 2013, 07:07:49 AM »
NO DOUBT SUZUKI COUPLING!  I will caution you though if you have never done it……read about it like you were a novice before you try it again, as I screwed it up about 4 times before success (and I had done it in undergrad)!

I failed once already.
I dont know how to make the boronic acid from like 1-bromooctane..
What I did was making a 1-bromooctane grignard first, and then treated with triisopropylborate. And then I just added  3-bromobenzaldehyde with the Pd(Oac)2 catalyst and stirred at r.t for one day.

Offline Dan

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Re: How to substitute this bromine group with alkyl chain?
« Reply #8 on: November 09, 2013, 06:42:42 PM »
You may encounter stability problems with alkylboronic acids/esters. An alkyl tetrafluoroborate will probably be better. Check out the work of Gary Molander, he's developed some nice methods for alkylating aryl halides.

You may also want to consider Negishi coupling.
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Offline orgopete

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Re: How to substitute this bromine group with alkyl chain?
« Reply #9 on: November 10, 2013, 10:49:10 AM »
Since you seem to actually be trying this reaction, I'd also consider doing a Heck reaction and reductive the product.

Or, use an acetylene with copper catalyst and reducing as per AlphaScent's suggestion.
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