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Topic: Complex chelating reaction table problem  (Read 2332 times)

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Offline webassignbuddy

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Complex chelating reaction table problem
« on: November 18, 2013, 10:01:17 AM »
How would I go about answering this question:



I tried making a table but it's proven to be a little more difficult than I thought it would be.

Table calculations
  • 25 ml x (0.35 mmol/mL) = 8.75 mmol RWW
  • Hg molar mass = 200.59 g = 200590 mg
    510 mg x (1 mmol/200590 mg) = 0.00250 mmol Hg

--------- Hg2+ ---- + ---- 2 RWW --- ::equil:: ------- Hg(RWW)22+
i-------(0.0025)------------(8.75)---------------------(0) mmol
Δ--------(-x)-----------------(-x)---------------------(+x) mmol
f------(0.0025-x)---------(8.75-x)--------------------(x) mmol

That doesn't look right....

Offline webassignbuddy

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Re: Complex chelating reaction table problem
« Reply #1 on: November 20, 2013, 10:28:16 AM »
Can anyone help me tackle this problem?

Offline Borek

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Re: Complex chelating reaction table problem
« Reply #2 on: November 20, 2013, 11:22:54 AM »
1. Number of moles is not the concentration.

2. You have ignored reaction stoichiometry in your ICE table.
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