[Jayasudha]

Hi Engineers, i would like to share how to calculate normality and molarity in a simple manner we well know, Normality= Molar mass of the solute/(Equivalent Wt*Volume of the solution in Ltr) like that Molarity=No of moles of solute/volume of the solution in ltr. i take EDTA for calculating how many mass required to prepare 0.05M Mol Wt of EDTA= 372.24g by formula Molarity=((mass of the solute/molar mass of the solute)/vol. of the solution in ltr) 0.05M =?/372.24 0.05*372.24=mass of the solute 18.612g of EDTA required to prepare 0.05M of EDTA this question may arise 0.05M is how many normality we could easily find the answer by the above formula Normality=Wt of Substance(EDTA)/Equivalent wt(EDTA)*volume in Ltr(take 1ltr) Equivalent Wt=Molar Mass/Mole Mole=Molar Mass/Atomic Mass Mole of EDTA= 372.24/83.016 =4moles then the Equivalent wt=372.24/4=93.06 Equivalent=Mass of component/Equivalent wt therefore, =372.24/93.06 =4 Normality= 372.24/4=93.06 so to prepare 1M dissolve 372.4g of EDTA in lit to prepare 1N dissolve 93.06g of EDTA in ltr if any correction pls let me know