[Radu]

   Hi!
 
  I have to prove that [RuO₃(OH)₂]^2- is a paramagnetic compound, while [OsO₂(OH)₄]^2- is diamagnetic. I applied the crystal field theory: ok, for the octhaedral compound, a Jahn-Teller distortion occurs, the degeneracy is lowered and the electrons couple( in d_xy orbital). But I don't understand how I can apply the CF theory to Ru complex, which is not Oh or Td. How can I find the d orbitals energetical distribution for, say, a NC=5 complex ( I think its geometry is trigonal bipiramid)
       Any ideas?
   

[kriggy]

Please delete

[Radu]

 I was talking about the rhutenium complex, the osmium one is Oh(  NC=6) , how can l prove its paramagnetism?

[kriggy]

yea I missread that.
Anyway, from some googling its same as RuO₄^2-.H₂O so it means that Ru has only 2 valence electrons so if you fill them into the orbitals http://en.wikipedia.org/wiki/Crystal_field_theory
you get 1 in each so its paramagnetic.
 

[Radu]

  I appreciate your help, thanks!! now it's clear to me, I found the degeneracies for trigonal bipiramid