[rmszymanski726]

I am attempting to solve this probelm but after trying several different methods (ICE table) I can't figure it out:
Sodium benzoate (C6H5CO2Na) is used as a food preservative.
a. Calculate the pH in 0.056M sodium benzoate; Ka for benzoic acid (C6H5CO2H) is 6.5×10−5.
b. Calculate the concentrations of all species present (Na+, C6H5CO−2, C6H5CO2H, H3O+ and OH−) in 0.056M sodium benzoate.

[Borek]

Let's start with a. Show what you did.

[DanChen2014]

C₆H₅CO₂^- + H₂O =====C₆H₅CO₂H + H₃O⁺

K_b=K_w/K_a

[Borek]

C₆H₅CO₂^- + H₂O =====C₆H₅CO₂H + H₃O⁺

Think it over.

[DanChen2014]

C₆H₅CO₂^- + H₂O =====C₆H₅CO₂H + H₃O⁺

K_b=K_w/K_a

CORRECTION:
C₆H₅CO₂^- + H₂O =====C₆H₅CO₂H + OH^-

YOU will have pOH.