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Topic: alcohol formation mechanism  (Read 2582 times)

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Offline Penguinone

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alcohol formation mechanism
« on: February 28, 2014, 11:46:34 AM »
Question:Give mechanistic reasoning for the following observations: CH3  +  excess CH2O --> [OH- H2O] C(CH2OH)4
Attempt see below:

NB:I am particularly stuck on getting the last hydroxyl group to work.

Any help will be greatly appreciated.

Offline Penguinone

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Re: alcohol formation mechanism
« Reply #1 on: February 28, 2014, 11:57:05 AM »
Maybe the last hydroxyl group is made by a crossed Cannizzaro reaction with formaldehyde?

Online AlphaScent

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Re: alcohol formation mechanism
« Reply #2 on: February 28, 2014, 12:31:12 PM »
Cannizzaro makes sense, but would not give desired product.  Would give the trihydroxyl carboxylic acid and methanol.

Are you sure its not the acid is to certainty the tetrahydroxyl moiety you are looking for Penguinone?

Cannizzaro is also classically a disproportionation, this is not. 
If you're not part of the solution, then you're part of the precipitate

Offline clarkstill

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Re: alcohol formation mechanism
« Reply #3 on: February 28, 2014, 12:35:18 PM »
Penguinone is right Alpha, you're doing the Cannizzaro the wrong way round... if you use formaldehyde as the source of hydride to reduce the final tri(hydroxymethyl) acetaldehyde, you get the correct product.

Online AlphaScent

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Re: alcohol formation mechanism
« Reply #4 on: February 28, 2014, 01:22:33 PM »
AHHHHHHHHH, so you are saying the formaldehyde is the source of the hydride and a hydroxyl would be kicked out?
If you're not part of the solution, then you're part of the precipitate

Online AlphaScent

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Re: alcohol formation mechanism
« Reply #5 on: February 28, 2014, 02:12:54 PM »
I was wrong.  It would be a crossed Cannizzaro reaction.  The formaldehyde is the reductant, oxidized to sodium formate (formic acid upon work-up) and the correspnding alcohol. 

Good Stuff.
If you're not part of the solution, then you're part of the precipitate

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