However, I do see one complication. Are you familiar with the concept of magnetic equivalence? Two nuclei can have the same chemical shift but not be magnetically equivalent. Whether or not this issue explains your spectra, I could not say, but it might be worth thinking about.
I'm not familiar with that concept but I'll learn it now that you mentioned it. The FID in this case though looks like something went completely wrong, I'm just not sure what. It looks like none of the F atoms got excited, otherwise there'd be something at the start of the FID, at first I thought maybe I knocked off all the F atoms on the starting material, but if that was the case (if there are no F atoms present), why didn't I get a straight line on my chemical shift spectrum?
Either way though, my theory is that there were no F atoms present in whatever I ran the NMR on. That would be an interesting result, but I have to be sure. Replacing those 4 electron withdrawing F atoms with electron donators will greatly alter the aromaticity of the benzene ring, but I'm not sure how to analyse that kinda thing. UV spectroscopy maybe? The colour that the product fluoresces at is the same as the starting material, I'm not entirely sure what that means, but I bet they absorb UV light at different frequencies (well I'm pretty sure of that, would make no sense if they didn't).
EDIT: Anyone know what wavenumber an aromatic C-F stretch or bend appears at on an IR spectrum? I haven't purified anything enough for C13 NMRs but I suppose an IR spectrum will tell me a thing or two about whats going on.