November 27, 2024, 07:29:55 AM
Forum Rules: Read This Before Posting


Topic: Dissociation degree calculation from Ka1 Ka2 and H+  (Read 5706 times)

0 Members and 1 Guest are viewing this topic.

Offline willy.Jonathan.12

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Dissociation degree calculation from Ka1 Ka2 and H+
« on: September 02, 2014, 05:41:31 PM »
Hello
My task is to express dissociation degree for fully dissociated form of diprotoic acid in general as a function of Ka1 Ka2 and [H+].

I know that
Ka1=[H+]*[HA-]/[H2A]
Ka2=[H+]*[A2-]/[HA-]
[HA-]+[A2-]=[H+]

diss degree=[A2-]/(HA-]+[H2A]+[A2-])

But I have no idea how to exchange all this things with only Ka1 Ka2 and [H+]
Can someone help me with that ?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27862
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Dissociation degree calculation from Ka1 Ka2 and H+
« Reply #1 on: September 02, 2014, 06:16:01 PM »
See

http://www.chembuddy.com/?left=pH-calculation&right=pH-polyprotic-acid-base

(while it aims at something else, it contains all formulas you need).
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links