[neon]

A sample of water from a large swimming pool has a resistance of 10000Ω at 25C when placed in a certain conductance cell. When filled with 0.02M KCl solution, the cell has a resistance of 100Ω at 25C. 585gm of NaCl were dissolved in the pool, which was thoroughly stirred. A sample of this solution gave a resistance of 8000Ω. Molar conductance of NaCl at that concentration is 125 and molar conductivity of KCl at 0.02M is 200Ω. Find volume of water in litres.

My attempt:

I found the cell constant to be 0.4.
[itex]k(NaCl) = \frac{0.4}{8000} [/itex]

125 = 1000*k(nacl)/M

Plugging all the values gives me the wrong answer.

[Borek]

Plugging all the values gives me the wrong answer.

Plugging them into what?

[neon]

Plugging all the values gives me the wrong answer.

Plugging them into what?

Substituting the value of k(NaCl) into the second equation.

[Borek]

Sorry, I did my best to understand what you did, but it is way too cryptic, I give up. If you want to be helped you need to explain your approach in such a way we don't have to spend time guessing what is teh equation you are using, which number is what and why it is used there.

If cell constant is 0.4, your first equations is basically 8000=1.