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Topic: Asking about fomula of protease activity (bromelain)  (Read 2866 times)

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Offline penhimdangyeu

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Asking about fomula of protease activity (bromelain)
« on: May 03, 2014, 01:56:51 PM »
Could you please explaining for me how can this fomula be established. I do the experiment to explore the enzymatic activity of bromalein (extracted from pineaple).

The Standard Tyrosine has concentration of 0.045% (45mg Tyr dissolved in 100 mL HCl 0.2 N)
Water sample
Enzyme solution

OD1 = OD of water tube
OD2 = OD of Tyrosine tube
OD3 = OD of Enzyme tube

DeltaOD(2)=OD2-OD1
DeltaOD(3)=OD3-OD1

The fomula in the book is
(450*DeltaOD(3)*X1)/(DeltaOD(2)*X2*10) (UI/mL)

10 is time of reaction
X1: mL of Tyrosine put in
X2: mL of Enzyme put in

But I dont understand why they get this fomula


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