I see this question/problem differently. The addition in question is an uphill reaction in that an alkene is a very weak base and bromide or water are stronger bases. A reaction with the alkene is a kinetic event that occurs in the presence of a greater thermodynamic equilibrium. Adding another base like acetone can shift the equilibrium or be a reactive reagent.
I suggest looking up the pKa's of the conjugate acids. I don't recall the value of acetone, but it will be protonated before the alkene. Protonating acetone will not automatically result in an aldol condensation, there are many more steps that must occur. However, a protonated ketone can react with an alkene. Depending on the concentrations, reaction rates, etc, I think this is likely to be the reaction you will find. However, the reaction will not stop there. Addition to the alkene will generate a stronger and in the case of acetone, a more easily eliminated base.
I think this reaction will give a mess. It may include an acid catalyzed aldol product(s). Without the alkene, clean and high yield acid catalyzed aldol reaction are difficult to find. That is virtually easily predicted if you consider the concentrations of reactants likely to be present. With an alkene present, this prediction is even more difficult. Look up Prins reaction.