I'm not an expert whatsoever, but would like to share my thoughts. This reaction is not a simple nucleophilic aromatic substitution, but proceeds via a catalytic cycle.
The rate determining step in general is the oxidative addition of the halide bond to the metal. Apparently the halide bond at position 4 is cleaved first.
I can't tell with 100% certainty whether the 2-position or the 4-position is less or more electron dense.
I'm curious how did you found out it was the 4-product? (NOESY, HMBC)?