November 28, 2024, 07:04:36 PM
Forum Rules: Read This Before Posting


Topic: Finding entropy with Temperature and K  (Read 4069 times)

0 Members and 1 Guest are viewing this topic.

sally125

  • Guest
Finding entropy with Temperature and K
« on: April 06, 2006, 11:53:17 PM »
For a reaction, the equilibrium constant K has the values K = 1.0 x 10^–2 at 100°C and K = 5.0 x 10^2 at 200°C. The value of ?Ho for this reaction is approximately what?

I have absolutely no idea how to do this.  I know how to find the deltaG of each.
Help?

Offline Hunt

  • Chemist
  • Full Member
  • *
  • Posts: 240
  • Mole Snacks: +25/-7
  • Gender: Male
Re:Finding entropy with Temperature and K
« Reply #1 on: April 07, 2006, 07:43:22 PM »
Pretty straight forward,

ln (K2 / K1 ) = (?H/R) (1/T2 - 1/T1)

This will give you an approximate value of ?H. Make sure you use R=8.314 J/mol.K to obtain ?H in Joules. ( T in Kelvin )

Sponsored Links