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determination of the chemical formula
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Topic: determination of the chemical formula (Read 1959 times)
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johnnyjohn993
Regular Member
Posts: 13
Mole Snacks: +0/-0
determination of the chemical formula
«
on:
October 20, 2014, 06:33:41 AM »
1.375g of Mannitol completely reacted with oxygen thus producing 1.993g CO
2
and 0.9519g water what is the empirical formula of Mannitol.
umm I really don't know where to start. pls help
all i know is the oxygen has a mass of 1.5699g
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Arkcon
Retired Staff
Sr. Member
Posts: 7367
Mole Snacks: +533/-147
Re: determination of the chemical formula
«
Reply #1 on:
October 20, 2014, 08:51:39 AM »
Quote from: johnnyjohn993 on October 20, 2014, 06:33:41 AM
all i know is the oxygen has a mass of 1.5699g
Really? That's pretty good. How did you get that number. Begin with a balanced reaction. You don't know the formula for a reactant, so put a place holder [mannitol]. But can you see where the carbon dioxide and what came from? How much carbon and hydrogen is that? Careful, mannitol may provide some of its own oxygen.
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Hey, I'm not judging. I just like to shoot straight. I'm a man of science.
johnnyjohn993
Regular Member
Posts: 13
Mole Snacks: +0/-0
Re: determination of the chemical formula
«
Reply #2 on:
October 22, 2014, 03:45:17 AM »
I got the answer now, I use the mole concept that is, our reactant have the same total amount of mole to the sum of the moles of the the product
cool
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determination of the chemical formula