[beethove]

K, this seems too easy, but I keep getting the wrong answer.

An electron is located at the origin of the coordinates, and a second electron is brought to a position 2 Å from the origin. Calculate the force between the two electrons.

 So... F= kq1q2/r2
 Then... F = 9 x 10to9th (1.602 x 10to-19 C)(1.602 x 10to-19 C)/ (2)(1x10to-10)squared

Right?
I get 5.766 x 10to-9 N
But the book says 7.1999 x10to-9 N
HELP, PLEASE.

[Borek]

Your answer looks OK to me.

[tex]F = 9 \times 10^9 \frac{(1.602\times10^{-19})^2}{(2\times10^{-10})^2} = 5.77 \times 10^{-9}[/tex]

[beethove]

Thanks!