It may be clearer on a graph. As you can see, an isobaric expansion must involve a temperature rise. For an adiabatic expansion, however, the work must come from the internal energy, so temperature falls. For an equilibrium adiabatic expansion, the line follows PVγ = constant. If Pext < Pgas, the work done is less and the temperature drop is less; in the limit of zero work the line will coincide with the isotherm. But I hope you can see it will never coincide with the isobar.