Dan: I like your ideas with the alkene metathesis
. I messed up my synth should convert the acid to ketone before the double bond is dihydroxylated.
(I'm here to learn)
Why do you hydrolize acetyl groups with LiOH? Any reason to choose it instead of NaOH or other option?
Great post!
Thanks! Doing these types of problems is definitely the best way to learn o-chem!
As for why I chose LiOH, it was mostly because that's what I used in lab! There are many cases where the difference between Li, Na, and K will give you a change in rates or selectivity. For instance LiBH4 reduces ketones with a ten fold rate increase over NaBH4. The rational I've heard for this is that the lithium binds more strongly to the carbonyl oxygen, thus activating the ketone during the rate-limiting step, addition of the hydride. I've heard a similar argument for the hydrolysis of esters with LiOH/MeOH/H2O. Supposedly it forms a six-membered transition state to help activate the carbonyl (see picture). Take this explanation with a huge grain of salt because I can't find any paper that supports this hypothesis or the fact that LiOH does have a faster rate compared to NaOH or KOH. Maybe some of the more experienced members would know better.
Interestingly when 2,2,2-cryptand or a crown ether is used, the yield drops considerably; LAH reductions wont go without Li, so a logical conclusion is to substitute Li with a lewis acid and it changes the yield from good to quantitative (i.e. 100%). FeCl3, CoCl3, etc. do this with LAH; I think this is an example of the elegance in details, and how they can lead to perfection when textbook reasoning says H
-+electrophile will react. Really reducing agents are not H
-. Even R-Li compounds are covalently bonded to Li