I found this reaction and I just want to make sure, is this just a wittig? I didnt think that PPh
3 is strong enough base to form the ylide needed for this reaction - to remove the Cl
- Or is it just easier since it is double alkylation of PPh
3 thus not needing a base?
Or could it be done with bromoform in a similar manner?
I suppose that dichlormethane doesnt react because bromine is better leaving group-and increasing the temperature/time could make it react too?
And one more: is there a way to convert ketone/aldehyde into halogenderivate (C=O
C-X) in one step? Or do I need reduction+substitution?