Why are there 2 signals for the M+ ion? What does this tell you?
this is where I am having trouble. Do I subtract 166 from 87 and that is the M+?
This is what I have so far and idk if its even right
The mass spectrum is presented as a vertical bar graph, in which each bar represents an ion having a specific mass-to-change
ratio and length of the bar indicated the relative abundance of that ion. I used the mass spectrum to identify the formula and the formula will give me the degree of unsaturation(DU). I first started by looking at the base peak which is the tallest peak (100%). In the above mass spectra for unknown one the
base peak is 87(M). The M+1 value is m/z= 88 (4.7%).The M+1 value is 88 since we know that the definition of M+1 is a molecular ion whose
mass is one amu higher than M. 88 amu is one amu higher than the m/z of M so it must be the M+1 value. Dividing the relative abundance of M+1 (4.7%) by 1.1% gives 4.27 and using the rounding rules it becomes 4. 4 carbons are in the analyte molecule.
M+2 shows whether or not sulfur, chlorine or bromine is present, because these are the only isotopes that have significant peaks. By scaling M to 100% and finding the relative abundances of sulfur, chlorine, and bromine through their natural abundances of M versus M+2, we can determine the intensity ratio of M / (M+2). I learned the following information to help identify sulfur, chlorine and bromine, “The intensity ratio of M compared to M+2 for sulfur is 100:4.4. Thus the M+2 intensity ratio for a compound containing sulfur will be about 4.4%. The same rule can be applied to chlorine and bromine which yield intensity ratios of about 31.9% and 97.2% respectively.”