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Topic: Ethylbenzene Transformation  (Read 1676 times)

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Offline ricecake

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Ethylbenzene Transformation
« on: March 20, 2015, 09:50:19 PM »
Ethybenzene + HNO3/H2SO4,t°  :rarrow: A + KMnO4,t° +H2O :rarrow: B+Na2S,t°  :rarrow: C +HNO2,0-5°C,HBF4,t°

Please help with this problem. I am a bit iffy about the position of NO2 group and Na2S

A would be p-nitroethylbenzene?
B would be c1cc(CC(O)=O)ccc1(N=O(=O))
C would be c1cc(CC(O)[-O].[Na+])ccc1(N=O(=O))
D would be c1cc(CC(O)[-O].[Na+])ccc1(F)

Offline Dan

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Re: Ethylbenzene Transformation
« Reply #1 on: March 21, 2015, 04:13:36 AM »
1. Your nitro groups have gone crazy. I assume this is a SMILES typo - use N(=O)=O, not N=O=O.
2. Look up the regioselectivity of permanganate oxidation of aromatic hydrocarbons.
3. So you are suggesting Na2S reduces an acid to a hydrated aldehyde. You are on the right track with reduction, but it won't reduce the carboxylic acid - something else...
4. It looks like you have identified this as diazonium chemistry - but, have you ever seen the formation of diazonium salts from nitroarenes? What functional group normally forms a diazonium with HNO2? This gives you a big clue about step 3.
« Last Edit: March 21, 2015, 09:42:38 AM by Dan »
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Offline ricecake

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Re: Ethylbenzene Transformation
« Reply #2 on: March 21, 2015, 09:23:46 AM »
Thank you so much for your help.
Yes, step B was a smiles typo. Is this closer to the correct answer?

A is still p-nitroethylbenzene
B is p-nitrobenzoic acid (the CH3 will fall off from the branch)
C is c1(c(=o)o)ccc(n)cc1
D is c1(c(=o)o)ccc(F)cc1
« Last Edit: March 21, 2015, 10:40:16 AM by ricecake »

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