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Topic: Mole to Mass (reaction of calcium carbonate with hydrochloric acid)  (Read 3576 times)

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Offline LysergicAcid

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Pearls are composed mainly of calcium carbonate. If you put them in acid, they will dissolve. If you have .025 mol of hydrochloric acid, what is the mass of water this produced? CaCo3 + 2HCl --> CaCl2 + H2O + CO2

what I tried: So, I see that two moles of hcl are needed to produce one mole of water. This is a 2 to 1 ratio. I figured, if they give me .025 mole of hydrochloric acid, that the moles of water should be proportionally the same. .025/2 = .0125 mole of h20. then, I should just multiply this mole by the mass/mol of h20.
.0125mol * 18g/mol = .225 grams of of water.

Is this answer correct?
I ask, because this question came from an online quiz, and the answer responses they have are:
A. 108g
B. 1.08g
C. 10.8g

thanks!
« Last Edit: April 11, 2015, 01:55:50 AM by LysergicAcid »

Offline Borek

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Re: Mole to Mass (reaction of calcium carbonate with hydrochloric acid)
« Reply #1 on: April 11, 2015, 03:08:20 AM »
.025/2 = .0125 mole of h20. then, I should just multiply this mole by the mass/mol of h20.
.0125mol * 18g/mol = .225 grams of of water.

Looks OK, must be an error in the quiz.
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