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Topic: Iodine clock reaction  (Read 2148 times)

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Offline venuscompass

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Iodine clock reaction
« on: May 20, 2015, 02:51:05 PM »
I am given Volume of KIO3 (ml): 10.0, 9.0, 7.0, 5.0, 3.0
I am given Volumbe of H2O (ml): 0.0, 1.0, 3.0, 5.0, 7.0

I also have the time for these reactions

The questions I need help with are:

1. Calculate the [KIO3] after the initial dilution (the original [KIO3] was 0.020M

2. Calculate the [KIO3] in the final mixture for each of the dilutions. Solution A and Solution B each had a volume of 10.0mL prior to mixing.

For initial would I go (example)
(0.020M x7.0mL)/ 10.0mL to find initial concentration?

What equation should I use to find the final concentration?
« Last Edit: May 20, 2015, 05:41:15 PM by Dan »

Offline venuscompass

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Re: Iodine clock reaction
« Reply #1 on: May 21, 2015, 08:33:27 PM »
in case anyone is viewing this question and needed help.

Question 1 is correct.

Question 2 you would use the new concentration found in Q1 and divide it by 2. Diluting it in half basically.


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