[cvc121]

Hi,

What is the concentration of Li if there is 200mL of Li₂SO₃ solution?

Here is my attempt:

First,I converted 200mL to 0.2L.
Then I calculated the Li concentration to be (1.5M)(2) = 3.0M.

Should I now multiply the 3.0M by 0.2L? Does the 0.2L even need to be considered?
Not sure what to do next.

All help is very much appreciated! Thanks!

[Corribus]

Then I calculated the Li concentration to be (1.5M)(2) = 3.0M.

You lost me with this. Where did you get 1.5M from? Did you forget to include part of the question wording?

[cvc121]

Yes. Forgot to mention that in the question. The solution is 1.5M.

[Corribus]

Presuming Li₂SO₃ fully dissociates into ions, how many moles of lithium ions will there be for every more of Li₂SO₃? You seem to have already figured this out, and that would be the end of it. The volume is inconsequential to the concentration. It's basically a decoy to throw you off.