In a normal phase HPLC setup the sample components are generally polar in nature, stationary phase (SP) is polar as well while the mobile phase (MP) is non-polar. So we if had 3 sample components A=least polar, B=intermediate polarity and C=most polar. Sample A is least attracted to the SP compared to B and C so it will be eluted out first, followed by B then C.
Then if we were to run the same mixture with the same column and same operating conditions, but a more polar mobile phase how will the elution order change?
I thought that if the MP is more polar, the interaction between C-MP becomes stronger than B-MP or A-MP. Essentially interaction of analyte and mobile phase is as follows: C-MP>B-MP>A-MP. So using this trend C should be eluted out first instead. However, the interaction of the component and the stationary phase is as follows: C-SP>B-SP>A-SP and using this trend alone, A should eluted out first.
So generally the MP will be less polar than the stationary phase no matter what. So the C-SP>C-MP and B-SP>B-MP and A-SP>A-MP still. I feel like this should tell me the elution order but I can't seem to get it. Can anyone explain this to me?